s^2+6sj-27j^2=

Solution for s^2+6sj-27j^2= equation:

Simplifying
s2 + 6sj + -27j2 = 0

Reorder the terms:
6js + -27j2 + s2 = 0

Solving
6js + -27j2 + s2 = 0

Solving for variable 'j'.

Factor a trinomial.
(-9j + -1s)(3j + -1s) = 0

Subproblem 1
Set the factor '(-9j + -1s)' equal to zero and attempt to solve:

Simplifying
-9j + -1s = 0

Solving
-9j + -1s = 0

Move all terms containing j to the left, all other terms to the right.

Add 's' to each side of the equation.
-9j + -1s + s = 0 + s

Combine like terms: -1s + s = 0
-9j + 0 = 0 + s
-9j = 0 + s
Remove the zero:
-9j = s

Divide each side by '-9'.
j = -0.1111111111s

Simplifying
j = -0.1111111111s
Subproblem 2
Set the factor '(3j + -1s)' equal to zero and attempt to solve:

Simplifying
3j + -1s = 0

Solving
3j + -1s = 0

Move all terms containing j to the left, all other terms to the right.

Add 's' to each side of the equation.
3j + -1s + s = 0 + s

Combine like terms: -1s + s = 0
3j + 0 = 0 + s
3j = 0 + s
Remove the zero:
3j = s

Divide each side by '3'.
j = 0.3333333333s

Simplifying
j = 0.3333333333s
Solution
j = {-0.1111111111s, 0.3333333333s}